hdu 1002 A + B Problem II 一直wrong answer,请高手看看哪错了#includeusing namespace std;int main(){\x05int inputNum;\x05char* pNum1=new char[1200];\x05char* pNum2=new char[1200];\x05int length1=0,length2=0,k=0;\x05int sum,carry=0;\x05char* p

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hdu 1002 A + B Problem II 一直wrong answer,请高手看看哪错了#includeusing namespace std;int main(){\x05int inputNum;\x05char* pNum1=new char[1200];\x05char* pNum2=new char[1200];\x05int length1=0,length2=0,k=0;\x05int sum,carry=0;\x05char* p

hdu 1002 A + B Problem II 一直wrong answer,请高手看看哪错了#includeusing namespace std;int main(){\x05int inputNum;\x05char* pNum1=new char[1200];\x05char* pNum2=new char[1200];\x05int length1=0,length2=0,k=0;\x05int sum,carry=0;\x05char* p
hdu 1002 A + B Problem II 一直wrong answer,请高手看看哪错了
#include
using namespace std;
int main()
{
\x05int inputNum;
\x05char* pNum1=new char[1200];
\x05char* pNum2=new char[1200];
\x05int length1=0,length2=0,k=0;
\x05int sum,carry=0;
\x05char* pResult;
\x05bool isZero=true;
\x05int removeZero=0;
\x05cin>>inputNum;
\x05int caseNum=1;
\x05if(inputNum20)
\x05{
\x05\x05return 0;
\x05}
\x05while(caseNum>pNum1>>pNum2;
\x05\x05inputNum--;
\x05\x05cout
怎么没人回啊

hdu 1002 A + B Problem II 一直wrong answer,请高手看看哪错了#includeusing namespace std;int main(){\x05int inputNum;\x05char* pNum1=new char[1200];\x05char* pNum2=new char[1200];\x05int length1=0,length2=0,k=0;\x05int sum,carry=0;\x05char* p
{ for(j=0;j