5x+6y+3x-4y+3-x+x =5x+3x-x+x+6y-4y+3 =8x=2y+3 谁能告诉我这题合并同类项的解题步骤啊,要按照题目.最好详细一点,快啊,明天半期考了,这题不会就完了：5x+6y+3x-4y+3-x+x合并同类项：=5x+3x-x+x+6y-4y+3=8x=2y+3

（x+y-5)*（x+y-5)+（x-y+3)=0 x*x-y*y 已知:3x-5y=0,求x/y,x-y/y,x-y/x 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 （5x+3y)(3y-5x)-(4x-y)(4y+x)= (3x-4y)(5x-4y)-(7x-8y)(6y-5x) x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2 6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5 （x+y）^6/(x+y)^4-(x-y)^5/(x-y)^3 化简 .. 4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2 先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5 {x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²= 因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+（x-3y)(x-5y)+(x-2y)(x-4y) (3x+4y)(5x-6y)=? 把(x-y)看做一个整体,合并同类项5(x-y)+2(x-y)-4(x-y)=3(x-y)次方-4(x-y)+7(x-y)-6(x-y)次方=