2x+4y=10 x+2y=5
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2x+4y=10 x+2y=5
2x+4y=10 x+2y=5
2x+4y=10 x+2y=5
2x+4y=10①
x+2y=5②
①-②×2,得0=0
所以①②方程同解,即原方程组只有一个独立方程,x+2y=5
所以有无数组解
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
x*x+2x+y*y-4y+5=0 x= y=
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
x+5y=4,2x+10y=?
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
3(2X+Y)+(2(2x-Y)=6 (8X+4y)-(10X-5Y)=2
4[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=39
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
4x-2*(10-x)-10=5y-3*(10-y)x+y=14
(x-4y)(2x+y)=