sin(π+x)=1/3,求sin(2π-x)+cos²(3π+x)的值

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sin(π+x)=1/3,求sin(2π-x)+cos²(3π+x)的值

sin(π+x)=1/3,求sin(2π-x)+cos²(3π+x)的值
sin(π+x)=1/3,求sin(2π-x)+cos²(3π+x)的值

sin(π+x)=1/3,求sin(2π-x)+cos²(3π+x)的值
sin(π+x)=1/3
sinx=-1/3,cos^2 x=1-(1/3)^2=8/9
sin(2π-x)+cos²(3π+x)
=sin(-x)+cos^2 (π+X)
=-sinx+cos^2 x
=1/3+8/9
=11/9

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