杭电ACM比赛的题目B.Little Elephant and NumbersTime Limit :4000/2000ms (Java/Other) Memory Limit :524288/262144K (Java/Other)Total Submission(s) :33 Accepted Submission(s) :12Problem DescriptionThe Little Elephant loves numbers.He has a positiv

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杭电ACM比赛的题目B.Little Elephant and NumbersTime Limit :4000/2000ms (Java/Other) Memory Limit :524288/262144K (Java/Other)Total Submission(s) :33 Accepted Submission(s) :12Problem DescriptionThe Little Elephant loves numbers.He has a positiv

杭电ACM比赛的题目B.Little Elephant and NumbersTime Limit :4000/2000ms (Java/Other) Memory Limit :524288/262144K (Java/Other)Total Submission(s) :33 Accepted Submission(s) :12Problem DescriptionThe Little Elephant loves numbers.He has a positiv
杭电ACM比赛的题目
B.Little Elephant and Numbers
Time Limit :4000/2000ms (Java/Other) Memory Limit :524288/262144K (Java/Other)
Total Submission(s) :33 Accepted Submission(s) :12
Problem Description
The Little Elephant loves numbers.
He has a positive integer x.The Little Elephant wants to find the number of positive integers d,such that d is the divisor of x,and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1≤x≤109).
Output
In a single line print an integer the answer to the problem.
Sample Input
1
10
Sample Output
1
2
Source
Codeforces
我不明白它说要找出一个除数,至少和原来的数有一位的数字相同,但它给的10和2没有一位是相同的啊,难道是我理解错了吗?

杭电ACM比赛的题目B.Little Elephant and NumbersTime Limit :4000/2000ms (Java/Other) Memory Limit :524288/262144K (Java/Other)Total Submission(s) :33 Accepted Submission(s) :12Problem DescriptionThe Little Elephant loves numbers.He has a positiv
注意是the number of positive integers d.即统计所有满足条件的d的数目.
10的话有1和10两个约数满足,所以输出2.
你应该懂了.直接暴力搜就可以了.

杭电ACM比赛的题目B.Little Elephant and NumbersTime Limit :4000/2000ms (Java/Other) Memory Limit :524288/262144K (Java/Other)Total Submission(s) :33 Accepted Submission(s) :12Problem DescriptionThe Little Elephant loves numbers.He has a positiv 哪里有ACM比赛的答案,哪个平台的题目都可以 杭电acm第3809题的详细思路 杭电ACM 3809的详细解题思路是什么 杭电acm怎么查看自己ac过的代码 杭电ACM比赛的一道题目,A.Shooshuns and SequenceTime Limit :4000/2000ms (Java/Other) Memory Limit :524288/262144K (Java/Other)Total Submission(s) :130 Accepted Submission(s) :34Problem DescriptionOne day shooshuns found a sequence of n integer 杭电acmd 字打错了,是 杭电acm的超时是什么意思 acm 1008 杭电 什么意思请帮我解释一下,谢谢!题目地址 http://acm.hdu.edu.cn/showproblem.php?pid=1008 杭电acm 什么思路啊 杭电acm 2034wrong answer Problem Description参加过上个月月赛的同学一定还记得其中的一个最简单的题目,就是{A}+{B},那个题目求的是两个集合的并集,今天我们这个A-B求的是两个集合的差,就是做集合 入门ACM题目,Problem Description无论是杭电的HDOJ,还是浙大的ZOJ,A+B问题都摆着第一个位置,不过大家都做过A+B,一模一样的题目显然太看不起大家了,所以我们改下规则,描述如下:我们定义26个字母(A 杭电acm 1008 题我的为什么是wrong answer 杭电acm 2035 题的算法是怎样的,杭电acm 2035 题的算法是怎样的,我要算法分析,不要代码!Problem Description求A^B的最后三位数表示的整数.说明:A^B的含义是“A的B次方”Input输入数据包含多个测试实 ACM这什么意思题目描述calculate a*(b+c-d)/e;输入there is one case.Give you five integers a,b,c,d,e(0 杭电ACM problem 1002 A + B Problem II为什么会WRONG ANSWER?计算结果没错啊?#include 杭电ACM第2136题Largest prime factor, A、B、C、D、E、F、六个足球队进行单循环比赛,当比赛到某一天时,统计出A、B、C、D、E五队已分别比赛了5、4、3、2、1场球,则还没有与B队比赛的球队是( A、C队 B、D队 题目中是这样的) D、F 为什么杭电acm 1013结果就是mod9的余数,这道题我的思路就是很土很土的办法,;