4a^2x^4y^5-9b^4z^2=?1/3m^2-3n^2=?a^2(a-2b)^2-36=?

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4a^2x^4y^5-9b^4z^2=?1/3m^2-3n^2=?a^2(a-2b)^2-36=?

4a^2x^4y^5-9b^4z^2=?1/3m^2-3n^2=?a^2(a-2b)^2-36=?
4a^2x^4y^5-9b^4z^2=?1/3m^2-3n^2=?a^2(a-2b)^2-36=?

4a^2x^4y^5-9b^4z^2=?1/3m^2-3n^2=?a^2(a-2b)^2-36=?
4a^2x^4y^5-9b^4z^2
错了,假设y次数是6
则=(2ax²y³)²-(3b²z)²
=(2ax²y³+3b²z)(2ax²y³-3b²z)
1/3m^2-3n^2
=1/3(m²-9n²)
=1/3(m+3n)(m-3n)
a^2(a-2b)^2-36
=[a(a-2b)+6][a(a-2b)-6]
=(a²-2ab+6)(a²-2ab-6)

(1)(x+y)^2-(x+y)^3(2)(x-y)-(x-y)^3(3)(x-y)^2-(y-x)^3(4)2(x-y)-3(y-x)^2(5)4ab(a=b)^2-6a^2b(a+b)(6)(x+y)^2(x-y)+(x+y)(x-y)^2(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)(9)(a-b)(b-a)^n(b-a)^2n-1 [两解)(10)2^2=3,2^b 将多项式X^2-4Y^2-9Z^2-12YZ分解成因式的积,结果是A.(x+2y-3z)(x-2y-3z)B.(x-2y-3z)(x-2y+3z)C.(x+2y+3z)(x+2y-3z)D.(x+2y+3z)(x-2y-3z) (z-x)2-4(x-y)(y-z)=0 求证x-2y+z=0 (提示:设x-y=a,y-z=b,则x-z=a+b)写错了是(z-x)的平凡-4(x-y)(y-z)=0 求证x-2y+z=0 (提示:设x-y=a,y-z=b,则x-z=a+b)那个平凡老是打不出来!sorry 3元一次方程组的过程a-2b=-9 b-c=3 2c+a=47 第一道 3x-y+z=4 2x+3y-z=12 x+y+z=6 第二道 y=2x-7 5x+3y+2z=2 3x-4z=4 第三道 (1) (a+2b/a-b)+(b/b-a)-(2a/a-b); (2) (y/x-y+z)+(2x+z/y-x-z)-(y-z/y-x-z); (3) (2/2a+3)+(3/3-2a)+(2a+15/4a^2-9); (4) (1/1-x)-(1/1+x)-(2x/1+x^2)+(-4x^3/1+x^4) a+b=3 x+y=3 x+y+z=26 b+c=-2 y+z=5 x-y=1 c+a=7 z+x=6 2x-y+z=18 三元一次方程组,3x+z=7 x-y=3 x-y+z=2x+y+2z=7 x+y=5 y+z-x=-52x+3y-z=12 2x-y+z=18 z-y-x=4对于回答全对者,本人会给予奖励, x,y,z 为实数且x+y+z=4√(x-3)+3√(y-6)=6√(z-5),则x+y+z=?x+y+z=4√(x-3)+2√(y-6)+6√(z-5)就可化成:a^2+b^2+c^2+14=4a+2b+6 5a-2b-+c=7 2a+b-2c=4 6a-5b+2c=10 ,x+2y=54x+5y+z=147x+10y-5z=27x-y=22x-z=-13x-y+2z=10x+2y-z=163x-5y+z=72x+5y-4z=39 解方程 1.x+3y/2=3/5 5(x-2y)=-4 2.3y-2x=4x-y/3=-1 3.a+b=5 b+c=3 a+c=14.x:y:z =1:3 :4 2x+y-z=25.x+y+z=5 2x-y-z=4 3x-2y-z=9急 五题解方程 求高手帮我算出来 五题全算出来啊 x+y=5 2x+3y-z=9 x-y+z=4 解下列方程组:a+b+c=-6,a-b+c-8,4a+2b+c=-11(2)3x-y+z=42x+3y-2z=123x+2y=66(3)2x-5y=-117y+4z=55x+2z=2(4)x+y+z=-12x-y-z=1x-2y+z=-4 解方程组2x/a+3y/b-4z/c=1,4x/a+2y/b-3z/c=3,3x/a+4y/b-2z/c=5 七年级数学下新学案92页.解方程组(3元1次,(1)y=2x-75x+3y+2z=23x-4z=4(2) x-2y=-9y-z=32z+x=47(3) x-y-z=0x+y-3z=42x+3y-5z=14(4) 2x+y+z=15x+2y+z=16x+y+2z=17(5) x+y-z=11y+z-x=5z+x-y=1(6) a+b+c=04a+2b+c=39a+3b+c=28 (1)y+3x+17=0 5y-2x+17=0 (2)x+y+z=12 x+2y+5z=22 x=4y (3)x+y+z=26 x-y=1 2x-y+z=18 (4)5x-2y=6 2y-z=-1 x-2z=18 (5)x+y-z=11 y+z-x=5 z+x-y=1 (6)a-2b-2c=-8 a+2c-1=0 a+3b-4c=1 (6) 解二元一次方程(1)a-b+c=4 a+b+c=3 2a+b+c=3(2)x-y-z=5 y-z-x=1 z-x-y=15(3)x-y=6 x+z=4 2x-y+2z=12 1.若自然数a,b满足,8a+10b>9ab,则a^2+b^2-a^2b^2+a^4+b^4-a^4b^4=?2.若实数x,y,z满足方程sqrt[x+5+sqrt(x-4)]+|x+y-z|/4=3,则(5x+3y-3z)^1998的末位数字是? 写出下列方程组的解集并化简(1)x+y=5,xy=6 (2)y^2=2x+3,x^2=2y+3 (3)3x+2y+z=13,x+y+2z=7,2x+3y-z=12 (4)y+z=a,z+x=b,x+y=c 1.x-y-z=1 2x+y-3z=4 3x-2y-z=-1 2.a+0.5b=c 0.5a-b-c=1 3a+b=-21.x-y-z=12x+y-3z=43x-2y-z=-12.a+0.5b=c0.5a-b-c=13a+b=-2