作业帮log2 x=log3 y=log5 z>0,则x的1/2次方.y的1/3次方.z的1/5次方的大小那是以2.3.5为底的对数
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log2 x=log3 y=log5 z>0,则x的1/2次方.y的1/3次方.z的1/5次方的大小那是以2.3.5为底的对数
log2 x=log3 y=log5 z>0,则x的1/2次方.y的1/3次方.z的1/5次方的大小
那是以2.3.5为底的对数
log2 x=log3 y=log5 z>0,则x的1/2次方.y的1/3次方.z的1/5次方的大小那是以2.3.5为底的对数
log(2)x=log(3)y=log(5)z>0,比较x^(1/2)、y^(1/3)、z^(1/5) 设log2,x=log3,y=log5,z=t>0 ==>x=2^t,y=3^t,z=5^t ==>x^(1/2)=2^(t/2),y^(1/3)=3^(t/3),z^(1/5)=5^(t/5) 设m=x^(1/2)=2^(t/2),n=y^(1/3)=3^(t/3),p=z^(1/5)=5^(t/5) ==>m^6-n^6=[2^(t/2)]^6-[3^(t/3)]^6=2^(3t)-3^(2t)=8^t-9^tm^6m ==>m^10>p^10 ==>m>p 所以,p
若log2(x)=log3(y)=log5(z)
一道高一数学题对数log2,详见补充已知log2[log1/2(log2^x)]=log3[log1/3(log3^y)]=log5[log1/5(log5^z)]=0,试比较x,y,z的大小?
log2[log3[log5 125]]=?log2[log3[log5 125]]=?
log5[log2(log9/log3)]=?
log5[log3(log2^x)]=1,x=
log2 x=log3 y=log5 z>0,则x的1/2次方.y的1/3次方.z的1/5次方的大小那是以2.3.5为底的对数
已知log2[log4(log3x)]=log3[log5(log2y)]=0,求4更号x-y^1/5
已知log2[log4(log3x)]=log3[log5(log2y)]=0,求4更号x-y^1/5写过程
(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y)
已知log2[log1/2(log2x)]=log3[log1/3(log3y)]=log5[log1/5(log5z)]=0.求x2+y^3-z^5的值
如果log5[log3(log2 x)]=0,那么x^(1/3)等于
诺log2[log1/2(log2x)]=log3[log1/3（log3y）]=比log5[log1/5(log5z)]=o,较x,y,z大小关于2,3,5,1/2,1/3,1/5,都是下标,因为不会打.
log2(log5 x)=-1
log2(a)=log3(b)=log5(c)
log2^25*log3^2倍根号2*log5^9=
log2^5*log3^2倍根号2*log5^9=
log3 25×log2 27×log5 2^-3=_____
log5［log2（log3 9）］=