利用因式分解求x+3y=125(x≠y)时,(x²+2xy-3y²)÷(x-y)的值

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利用因式分解求x+3y=125(x≠y)时,(x²+2xy-3y²)÷(x-y)的值

利用因式分解求x+3y=125(x≠y)时,(x²+2xy-3y²)÷(x-y)的值
利用因式分解求x+3y=125(x≠y)时,(x²+2xy-3y²)÷(x-y)的值

利用因式分解求x+3y=125(x≠y)时,(x²+2xy-3y²)÷(x-y)的值
x²+2xy-3y²=(x-y)(x+3y)
所以原式=(x-y)(x+3y)/(x-y)=x+3y=125

(x²+2xy-3y²)÷(x-y)
=(x-y)(x+3y)/(x-y)
=x+3y=125